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发表于 2018-8-4 22:38:09
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O9007
#111=#5021
#112=#5022
M99
O9008
#121=#5021
#122=#5022
M99
O9009
#131=#5021
#132=#5022
#1=#111*[#122-#132]+#121*[#132-#112]+#131*[#112-#122]
IF[#1 EQ 0] THEN #3000=1(Error/3 In a staright line)
#2=[#111*#111+#112*#112-#121*#121-#122*#122]/2
#3=[#111*#111+#112*#112-#131*#131-#132*#132]/2
#4=#2*[#112-#132]-#3*[#112-#122]
#5=#3*[#111-#121]-#2*[#111-#131]
(半径-#30=SQRT[[#4/#1-#111]*[#4/#1-#111]+[#5/#1-#112]*[#5/#1-#112]])
#5221=#4/#1
#5222=#5/#1
#111=#0
#112=#0
#121=#0
#122=#0
#131=#0
#132=#0
M99 |
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